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{excerpt:hidden=true}Simple examples showing the utility of [initial-state final-state diagrams|initial-state final-state diagram] and [energy bar diagrams|energy bar diagram].{excerpt}

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{card:label=Part A}

h3. Part A: Initial-State Final-State Diagrams

Because the Work-Energy Theorem and the principle Law of Change for the [Mechanical Energy and Non-Conservative Work] model involve only the initial and final energies of the system, it is useful to devote considerable attention to understanding the system's configuration at those times.  It is customary to sketch the system in its initial and final configurations, labeling the quantities that are relevant for the kinetic and potential energies of the system.  

Suppose we were asked to determine the speed of a 0.25 kg block launched vertically from rest by a spring of spring constant 500 N/m that was initially compressed 0.10 m from its natural length when the block reaches a height of 0.50 m above the natural position of the spring.  How would you draw an initial-state final-state diagram for this situation?

h4. Solution

{toggle-cloak:id=sysA} *System:* {cloak:id=sysA}The block as [point particle] along with the spring ([massless object]) and the earth ([infinitely massive object]).{cloak:sysA}

{toggle-cloak:id=intA} *Interactions:* {cloak:id=intA}The system contains an interaction between the earth and the block due to [gravity|gravity (near-earth)], which will be represented as gravitational [potential energy], and also an interaction between the ground and the block mediated by the spring that will be represented as [elastic|Hooke's Law for elastic interactions] [potential energy].{cloak:intA}

{toggle-cloak:id=modA} *Model:* {cloak:id=modA}[Mechanical Energy and Non-Conservative Work]{cloak:modA}

{toggle-cloak:id=appA} *Approach:*

{cloak:id=appA}

 We can neatly summarize the given information through a two-panel diagram:

|!mecheex1i.png|vspace=150!|!mecheex1f.png!|
||Initial State||Final State||

{note}You could also choose a different zero point for the height, provided you adjust the initial and final heights accordingly.{note}

The act of drawing the diagram will often clarify the givens, and it will also remind us to choose a zero height for the gravitational potential energy.  

{cloak:appA}

{card:Part A}
{card:label=Part B}

h3. Part B: Energy Bar Graphs

Drawing and labeling the [initial-state final-state diagram] will give a good idea of where the [mechanical energy] is in the [system].  Thus, once the system is depicted, it is often useful to represent the energy distribution graphically as well.  This is done using a *bar graph* that contains one bar for each distinct type of energy that will make up the mechanical energy of the system.  This *bar graph* is not necessarily quantitative, but it should be drawn to reflect conservation of energy if the non-conservative work is zero.  

Continuing with the example from Part A, we can see that in the initial state the energy is divided among spring potential and gravitational potential, with zero kinetic energy present.  In the final state, the energy is divided among gravitational potential and kinetic energy, with the spring (returned to its natural position) contributing zero energy.  Draw a bar graph representation of these distributions.

h4. Solution

*System, Interactions and Model:* As in Part A.

{toggle-cloak:id=appB} *Approach:* 

{cloak:id=appB}

|!mechebar1i.png!|!mechebar1f.png!|
||Initial State||Final State||

Note that these bar graphs are scaled to show conservation of energy.  The sum of the three bars should be the same in each case.  We have made a guess, however, about the relative sizes of the kinetic and gravitational potential energies.  We cannot know which will be larger until we finish solving the problem.  We do know, however, that they add up to equal the initial mechanical energy.  Thus, a second reasonable guess would have been:

|!mechebar1i.png!|!mechebar2f.png!|
||Initial State||Final State||

Either is acceptable as an initial guess at the relative energies.  

{cloak:appB}

{card:Part B}
{card:label=Part C}

h3. Part C: Dealing with Non-Conservative Work

Initial-state final-state diagrams and energy bar graphs are also useful for detecting problems in which mechanical energy is _not_ conserved.  Consider the following example:

A 1500 kg roller coaster car is moving at a speed of 10 m/s moving with no friction when it crests the final hill at a height of 15 m above the end of the ride.  It then descends to a level area of track that extends for 20 m before the finish.  As soon as the car reaches the level track, it hits the brakes, coming to a stop exactly at the finish line.  Determine the effective coefficient of friction experienced by the car during braking.

Draw initial-state final-state and energy bar diagrams for this situation.

h4. Solution

{toggle-cloak:id=sysC} *System:* {cloak:id=sysC}Roller coaster car as [point particle] plus earth as an [infinitely massive object].  {cloak:sysC}

{toggle-cloak:id=intC} *Interactions:* {cloak:id=intC}The car-earth interaction through [gravity|gravity (near-earth)] will be represented as gravitational [potential energy].  The car also experiences an external interaction from the track ([kinetic friction] and [normal force]).  The friction part of this interaction will be represented as [non-conservative|non-conservative force] [work], while the [normal force] is irrelevant to the model as it does no [work] (being always perpendicular to the direction of travel).{cloak:intC}

{toggle-cloak:id=modC} *Model:* {cloak:id=modC}[Mechanical Energy and Non-Conservative Work].{cloak:modC}

{toggle-cloak:id=appC} *Approach:*

{cloak:id=appC}

For simplicity, we combine the initial-state final-state diagram and the energy bar diagram.

|!mecheex2i.png!|!mecheex2f.png!|
||Initial State||Final State||

With our choices of coordinates, it is clear that the mechanical energy is _not_ conserved in this problem.  Thus, we look for a source of non-conservative work.  This gives us a way to attack the friction force, which is the source of non-conservative work in this case.

{cloak:appC}

{card:Part C}
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