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Excerpt

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An

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interaction which has the potential to produce a change in the rotational velocity of a system about a specified axis.


Motivation for Concept

Forces applied to a body in an attempt to produce rotation will have different effects depending upon both their direction of application and their location of application. Most people have either accidentally or purposely experimented with opening a door by applying a force near the hinges and found it to be an inefficient procedure. Obtaining rotation is much easier when the force is applied far from the hinges (hence the placement of door handles opposite the hinges).

Location alone, however, is not enough to guarantee effective rotation. Consider another experiment. Suppose that you open a door so that it is ajar. Position yourself at the edge of the door opposite the hinges and push directly along the door toward the hinges. The door will not rotate, even with a hard push. This indicates that the direction of the force is also important to the rotation produced.

With these experiments in mind, we recognize that we must define a new quantity that describes the effectiveness of an interaction at producing rotation about a specific axis (in our examples, the axis was set by the line of the door hinges). This quantity is called torque.

Conditions for Single-Axis Torque

In introductory physics, it is sufficient (with the exception of certain very special cases like the gyroscope) to consider torques in one dimension. To ensure that the torques are single-axis, a situation must obey certain restrictions:

  1. All forces should be applied such that their vectors lie in a single plane. (For simplicity, we will call this the xy plane.)
  2. All objects in the system should have their center of mass constrained to move in the xy plane or else guaranteed to move in
    the xy plane because of the symmetries of the object (taking into account that all forces act in the xy plane).
  3. Any pre-existing spin of the objects must be directed perpendicular to the xy plane.

If these conditions are met, then the axis of rotation chosen for the system may be chosen perpendicular to the xy plane (parallel to the z-axis) and all torques will be either parallel to or anti-parallel to the z-axis (they will have zero x and y components).

Definition of Torque

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Cross Product

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Defining the torque resulting from a force requires two pieces of information:

  1. The force applied (magnitude and direction).
  2. The position (magnitude and direction) of the force's application with respect to the axis of rotation about which the torque is to be calculated.

The torque is most succinctly defined by using the vector cross product:

Latex
 which produces rotation.  

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h2. Motivation for Concept

Forces applied to a body in an attempt to produce rotation will have different effects depending upon both their direction of application and their location of application.  Most people have either accidentally or purposely experimented with opening a door by applying a force near the hinges and found it to be an inefficient procedure.  Obtaining rotation is much easier when the force is applied far from the hinges (hence the placement of door handles opposite the hinges).  

Location alone, however, is not enough to guarantee effective rotation.  Consider another experiment.  Suppose that you open a door so that it is ajar.  Position yourself at the edge of the door opposite the hinges and push directly along the door toward the hinges.  The door will not rotate, even with a hard push.  This indicates that the direction of the force is also important to the rotation produced.

With these experiments in mind, we recognize that we must define a new quantity that describes the effectiveness of an interaction at producing rotation about a specific axis (in our examples, the axis was set by the line of the door hinges).  This quantity is called torque.

h2. Conditions for One-Dimensional Torque

In introductory physics, it is sufficient (with the exception of certain special cases like the [gyroscope]) to consider torques in one dimension.  To ensure that the torques are one-dimensional, a situation must obey certain restrictions.

h4.  Motion in a Plane

To ensure that one-dimensional torques result, all objects in the system should have their center of mass confined to move in a plane, called the _xy_ plane.  Further, all forces should be applied such that their vectors lie in the _xy_ plane. 

h4.  Axis of Rotation Along z-Axis

Further, the axis of rotation chosen for the system must be perpendicular to the _xy_ plane, and so parallel to the z-axis. 

h2. Definition of Torque

h4. Cross Product

Defining the torque resulting from a force requires two pieces of information:

# The force applied (magnitude and direction).
# The position (magnitude and direction) of the force's application with respect to the [axis of rotation] about which the torque is to be calculated.

The torque is most succinctly defined by using the vector [cross product]:

{latex}\begin{large}\[\tau_{z} \equiv \vec{r}\times \vec{F} \]\end{large}{latex}

where τ is the torque, _r_ is the position of the point of application of the force with respect to the axis of rotation, and _F_ is the force.  Note that since the torque is assumed to lie in the +z or -z direction, we have specified its vector nature with the _z_ subscript rather than a vector arrow.

h4. Magnitude

In two dimensions, this formula is equivalent to:

{latex}

where τ is the torque, r is the position of the point of application of the force with respect to the axis of rotation, and F is the force. Note that since the torque is assumed to lie in the +z or -z direction, we have specified its vector nature with the z subscript rather than a vector arrow.

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Magnitude

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In two dimensions, this formula is equivalent to:

Latex
\begin{large}\[ |\tau_{z}| = rF\sin\theta\]\end{large}{latex}

where

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the

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angle

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θ is

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the

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angle

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between

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the

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position

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vector

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and

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the

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force

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vector.

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That

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angle

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should

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technically

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be

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found

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by

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extending

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the

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position

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vector

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and

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then

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taking

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the

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smaller

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angle

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to

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the

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force

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as

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shown here.

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The given vectors.

Step 1: Extend position vector.

Step 2: Choose the smaller angle to the force.

It is often helpful to make use of the fact that the sine of supplementary angles is the same, and therefore the closer angle between the position vector and force can also be used without extension as shown here.

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The given vectors.

Simply take the smaller angle between them.

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Direction

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Note that our second form of the equation for torque gives the magnitude only. To define the direction, the vectors r and F must be examined to determine the sense of the rotation. Since we are restricted to one-dimensional torques, we can describe the sense of the rotation as clockwise or counterclockwise. Examples of forces producing clockwise and counterclockwise torques are shown here.

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Counterclockwise

Clockwise

When constructing free-body diagrams for systems in which torques are of interest, it is important to draw them from the perspective of someone looking along the axis of rotation and to assign a mathematical sign (+ or -) to each sense of rotation. This is usually done as shown below.

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Counterclockwise rotation defined to be positive.

Clockwise rotation defined to be positive.

Note

If you are using explicit vector cross products to calculate the torque, then technically you must choose the positive sense of rotations to correspond with the positive z-axis and you must take care to construct a right-handed coordinate system. If you fail to do this, you will encounter sign errors when computing your cross products (the mathematical technique used to compute cross products assumes that a right-handed coordinate system is employed).

Parsing the Magnitude

It is sometimes useful to associate the sinθ portion of the formula for the magnitude of the one-dimensional torque with either the force or the position. These two possible associations lead to two terms that are often used in describing the rotational effects of a force: tangential force and moment arm.

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Tangential Force

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Suppose we group the formula for the magnitude of the torque in the following way:

Latex
 here.

|!obtuse1.png|height=150!|!obtuse2.png|height=150!|!obtuse3.png|height=150!|
|The given vectors.|Step 1: Extend position vector.|Step 2:  Choose the smaller angle to the force.|



h4. Direction

Note that this second form of the equation for torque is in terms of magnitude only.  To define the direction, the vectors _r_ and _F_ must be examined to determine the _sense_ of the rotation.  Since we are restricted to one-dimensional torques, we can describe the sense of the rotation as clockwise or counterclockwise.  Examples of forces producing clockwise and counterclockwise torques are shown here.

PICTURE

 When constructing free-body diagrams for systems in which torques are of interest, it is important to draw them from the perspective of someone looking along the axis of rotation and to assign a mathematical sign (+ or -) to each sense of rotation.  This is usually done as shown below.

PICTURE


h2. Parsing the Magnitude

It is sometimes useful to associate the sinθ portion of the formula for the magnitude of the one-dimensional torque with either the force or the position.  These two possible associations lead to two terms that are often used in describing the rotational effects of a force: tangential force and [moment arm].

h4. Tangential Force

Suppose we group the formula for the magnitude of the torque in the following way:

{latex}\begin{large}\[ |\tau_{z}| = r (F\sin\theta) \equiv r F_{\perp} \]\end{large}{latex}

where

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we

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have

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defined

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the

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tangential

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component

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of

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F

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as F sinθ. This name is chosen because, as shown in the pictures below, F sinθ is the size of the part of F that is directed perpendicular to r.

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Moment Arm

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If we instead group the formula as:

Latex
 _F_ sinθ.  This name is chosen because, as shown in the pictures below, _F_ sinθ is the size of the part of _F_ that is directed perpendicular to _r_.  

PICTURE

h4. Moment Arm

If we instead group the formula as:

{latex}\begin{large} \[ |\tau_{z}|= F (r \sin\theta) \equiv F r_{\perp} \] \end{large}{latex}

where

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we

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have

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defined

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a

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perpendicular

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component

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of

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r.

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In

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this

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case,

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we

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give

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the

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component

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the

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special

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name

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of

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moment

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arm

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.

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The

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moment

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arm

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can

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be

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thought

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of

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as

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the

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closest

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distance

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of

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approach

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of

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the

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line

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of

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action

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of

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the

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force

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to

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the

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axis

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of

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rotation,

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as

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is

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shown

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in

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the

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pictures

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below.

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