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Momentum

Excerpt

Mass times velocity, or, equivalently, a quantity whose time rate of change is equal to the net force applied to a system.

Motivation for Concept

Forces are actions which cause a change in the velocity of an object, but a given application of force will have very different results when applied to objects of very different mass. Consider the force imparted by a baseball player swinging a bat. When delivered to a baseball, the change in velocity is dramatic. A 95 mph fasball might be completely reversed and exit the bat moving 110 mph in the other direction. When delivered to a car, however, the change in velocity is miniscule. A car moving 95 mph will not be slowed noticeably by the action of a bat. Thus, although the change in velocity of a system is proportional to the force applied, it is not equal to the force applied. To define a quantity whose rate of change is equal to the force applied, we must include both the mass and velocity of the system subject to the force.

Mathematical Definition

Momentum of a Point Particle

The momentum (p) of a point particle with mass m and velocity v is defined as:

Latex
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h1. Momentum

{excerpt}[Mass|mass] times [velocity], or, equivalently, a quantity whose time rate of change is equal to the net [force] applied to a [system].{excerpt}

h3. Motivation for Concept

[Forces|force] are actions which cause a change in the [velocity] of an object, but a given application of [force] will have very different results when applied to objects of very different [mass].  Consider the [force] imparted by a baseball player swinging a bat.  When delivered to a baseball, the change in [velocity] is dramatic.  A 95 mph fasball might be completely reversed and exit the bat moving 110 mph in the other direction.  When delivered to a car, however, the change in [velocity] is miniscule.  A car moving 95 mph will not be slowed noticeably by the action of a bat.  Thus, although the change in [velocity] of a system is proportional to the [force] applied, it is not equal to the [force] applied.  To define a quantity whose rate of change is equal to the [force] applied, we must include both the [mass] and [velocity] of the system subject to the [force].

h3. Mathematical Definition

h4. Momentum of a Point Particle

The momentum (_p_) of a [point particle] with [mass] _m_ and [velocity] _v_ is defined as:

{latex}\begin{large}\[ \vec{p} \equiv m\vec{v}\]\end{large}{latex}

h4. Momentum of a System

For a [system] composed of _N_ objects which are approximated as [point particles|point particle] with their position specified by the objects' [centers of mass|center of mass], the [system] momentum is defined as the [vector] sum of the momentum of the [constituents|system constituent]:

{latex}

Momentum of a System

For a system composed of N objects which are approximated as point particles with their position specified by the objects' centers of mass, the system momentum is defined as the vector sum of the momentum of the constituents:

Latex
\begin{large}\[ \vec{p}^{\rm \: sys} = \sum_{j=1}^{N} m_{j}\vec{v}_{j} \]\end{large}{latex}

This

...

definition

...

is

...

completely

...

equivalent

...

to

Latex
 

{latex}\begin{large}\[ \vec{p}^{\rm \: sys} = M^{\rm sys} \vec{v}^{\rm \: CM} \]\end{large}{latex}

where _M_^sys^ is the total mass of the [system] and _v_^CM^ is the [velocity] of the [system's|system] [center of mass].

h3. Momentum and Newton's Laws

h4. Momentum and Newton's Second Law

One way of stating [Newton's Second Law] is that the rate of change of a [system's|system] momentum is equal to the [vector] sum of the [forces|force] 

where Msys is the total mass of the system and vCM is the velocity of the system's center of mass.

Momentum and Newton's Laws

Momentum and Newton's Second Law

One way of stating Newton's Second Law is that the rate of change of a system's momentum is equal to the vector sum of the forces applied to the object:

Latex
applied to the object:

{latex}\begin{large}\[ \frac{d\vec{p}^{\rm \: sys}}{dt} = \sum_{k=1}^{N_{F}} \vec{F}_{k} \] \end{large}{latex}

h4. Momentum and 

Momentum and Newton's

...

Third

...

Law

...

By

...

Newton's

...

3rd

...

Law

...

,

...

internal

...

forces

...

cancel

...

from

...

the

...

vector

...

sum

...

above,

...

leaving

...

only

...

the

...

contribution

...

of

...

external

...

forces:

Latex
|external force]:

{latex}\begin{large}\[ \frac{d\vec{p}^{\rm \:sys}}{dt} = \sum_{k=1}^{N_{F}} \vec{F}^{\rm ext}_{k} \] \end{large}{latex}

h4. Momentum and Impulse

The integrated change in momentum can be found explicitly by using the net [external|external 

Momentum and Impulse

The integrated change in momentum can be found explicitly by using the net external impulse (Jext):

Latex
force] [impulse] (_J_^ext^):

{latex}\begin{large}\[ \vec{p}^{\rm \:sys}_{f} - \vec{p}^{\rm \:sys}_{i} = \int_{t_{i}}^{t_{f}} \sum_{k=1}^{N_{F}} \vec{F}_{k}^{\rm ext} \:dt \equiv \sum_{k=1}^{N_{F}} \vec{J}_{k}^{\rm ext} \]\end{large}

Conservation of Momentum

Conditions for True Conservation

In the absence of a net external force, the momentum of a system is constant:

Latex
{latex}

h3. Conservation of Momentum

h4. Conditions for True Conservation

In the absence of a _net_ [external force], the momentum of a [system] is constant:

{latex}\begin{large}\[ \vec{p}_{f}^{\rm \:sys} = \vec{p}_{i}^{\rm \:sys}\]\end{large}{latex}

This

...

equation

...

is

...

normally

...

broken

...

up

...

to

...

explicitly

...

show

...

the

...

system

...

constituents

...

and

...

the

...

vector

...

components:

{
Latex
}\begin{large}\[ \sum_{j=1}^{N} p^{j}_{x,f} = \sum_{j=1}^{N} p^{j}_{x,i} \]
\[ \sum_{j=1}^{N} p^{j}_{y,f} = \sum_{j=1}^{N} p^{j}_{y,i} \]
\[ \sum_{j=1}^{N} p^{j}_{z,f} = \sum_{j=1}^{N} p^{j}_{z,i} \]\end{large}{latex}


h4. Approximate Conservation in Collisions

Because the change in

Approximate Conservation in Collisions

Because the change in momentum is proportional to the impulse, which involves a time integral, for instantaneous events:

Latex
 momentum is proportional to the [impulse], which involves a time integral, for instantaneous events:

{latex}\begin{large}\[ \lim_{t_{f}\rightarrow t_{i}} \int_{t_{i}}^{t_{f}} \vec{F}^{\rm ext} \:dt = 0 \]\end{large}{latex}

For

...

approximately

...

instantaneous

...

events

...

such

...

as

...

collisions,

...

it

...

is

...

often

...

reasonable

...

to

...

approximate

...

the

...

external

...

impulse

...

as

...

zero

...

by

...

considering

...

a

...

system

...

composed

...

of

...

all

...

the

...

objects

...

involved

...

in

...

the

...

collision.

...

The

...

key

...

to

...

the

...

utility

...

of

...

this

...

assumption

...

is

...

that

...

often

...

during

...

collisions

...

the

...

change

...

in

...

momentum

...

of

...

any

...

individual

...

system

...

constituent

...

being

...

analyzed

...

is

...

dominated

...

by

...

the

...

internal

...

collision

...

forces

...

(the

...

external

...

forces

...

make

...

a

...

negligible

...

contribution

...

to

...

that

...

constituent's

...

change

...

in

...

momentum

...

during

...

the

...

collision

...

).

{
Warning
}

Before

the

collision

occurs

and

after

the

collision

is

complete,

the

[

collision

forces

]

will

usually

drop

to

zero.

Neglecting

external

impulse

can

only

be

justified

_

during

_

the

collision.

It

is

also

completely

incorrect

to

say

that

the

momentum

of

each

_

object

_

is

[

conserved

]

.

Only

the

_

system

_

momentum

is

(approximately)

[

conserved

]

.

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