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Composition Setup

Excerpt

The time rate of change of velocity of an object, or alternately the net force on the object divided by the object's mass.

Mathematical Representation

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h1. Acceleration
{excerpt}The time rate of change of [velocity] of an object, or alternately the net [force] on the object divided by the object's [mass].{excerpt}

h3. Mathematical Representation 

{latex}\begin{large}\[ \vec{a} = \frac{d\vec{v}}{dt} \qquad \mbox{or} \qquad \vec{a}=\frac{\sum \vec{F}}{m} \]\end{large}{latex}

h3. 

One-Dimensional

...

Acceleration

Utility of the One-Dimensional

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Case

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As

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with

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all

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vector

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equations,

...

the

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equations

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of

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kinematics

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are

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usually

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approached

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by

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separation

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into

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components.

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In

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this

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fashion,

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the

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equations

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become

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three

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simultaneous

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one-dimensional

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equations.

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Thus,

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the

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consideration

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of

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motion

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in

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one

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dimension

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with

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acceleration

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can

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be

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generalized

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to

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the

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three-dimensional

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case.

Useful Digrammatic Representations

Several diagrammatic representations are commonly used to represent accelerated motion.

Deceleration

In physics, the term acceleration denotes a vector, as does velocity. When the acceleration of an object points in the same direction as its velocity, the object speeds up. When the acceleration of an object points in the direction opposite the object's velocity, the object slows down. In everyday speech, we would call the first case "acceleration" and the second case "deceleration". In physics, both cases represent acceleration, but with a different relationship to the velocity.

Constant Acceleration

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Integration with Respect to Time

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If acceleration is constant, the definition of acceleration can be integrated:

Latex



h4. Useful Digrammatic Representations 

Several diagrammatic representations are commonly used to represent accelerated motion.

* [*Position vs. Time Graph|position versus time graph]: {excerpt-include:position versus time graph|nopanel=true}

* [*Velocity vs. Time Graph|velocity versus time graph]: {excerpt-include:velocity versus time graph|nopanel=true}

* [Motion Diagram|motion diagam]: {excerpt-include:motion diagram|nopanel=true}

h4. Deceleration

In physics, the term _acceleration_ denotes a vector, as does [velocity].  When the acceleration of an object points in the same direction as its [velocity], the object speeds up.  When the acceleration of an object points in the direction opposite the object's [velocity], the object slows down.  In everyday speech, we would call the first case "acceleration" and the second case "deceleration".  In physics, both cases represent acceleration, but with a different relationship to the [velocity].  

h4. Constant Acceleration 

h5. {color:maroon} Integration with Respect to Time {color}

If acceleration is constant, the definition of acceleration can be integrated:

{latex}\begin{large}\[ \int_{v_{\rm i}}^{v} dv = \int_{t_{\rm i}}^{t} a\: dt \] \end{large}{latex}

For

...

the

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special

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case

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of

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constant

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acceleration,

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the

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integral

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yields:

{
Latex
}\begin{large} \[ v - v_{\rm i} = a(t-t_{\rm i}) \] \end{large}{latex}

which

...

is

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equivalent

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to:

{
Latex
}\begin{large} \[ v = v_{\rm i} + a (t-t_{\rm i}) \] \end{large}{latex}

We

...

can

...

now

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substitute

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into

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this

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equation

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the

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definition

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of

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velocity,

{
Latex
}\begin{large}\[ v = \frac{dx}{dt}\]\end{large}{latex}

which

...

gives:

{
Latex
} \begin{large} \[ \frac{dx}{dt} = v_{\rm i} + a t - a t_{\rm i} \] \end{large}{latex}

We

...

can

...

now

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integrate

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again:

{
Latex
} \begin{large} \[ \int_{x_{\rm i}}^{x} dx = \int_{t_{\rm i}}^{t} \left( v_{\rm i} - at_{\rm i} + a t\right)\:dt \]   \end{large}{latex}

to

...

find:

{
Latex
} \begin{large} \[ x - x_{\rm i} = v_{\rm i} (t-t_{\rm i}) - a t_{\rm i} (t-t_{\rm i}) + \frac{1}{2}a( t^{2} - t_{\rm i}^{2}) \] \end{large}{latex}

We

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finish

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up

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with

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some

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algebra:

{
Latex
}\begin{large}\[ x = x_{\rm i} + v_{\rm i} (t-t_{\rm i}) + \frac{1}{2} a (t^{2} - 2 t t_{\rm i} + t_{\rm i}^{2}) \] \end{large}{latex}

which

...

is

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equivalent

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to:

{
Latex
}\begin{large} \[ x = x_{\rm i} + v_{\rm i} (t-t_{\rm i}) + \frac{1}{2} a (t - t_{\rm i})^{2} \] \end{large}

...

Integration with Respect to Position

...

The definition of acceleration can also be integrated with respect to position, if we use a calculus trick that relies on the chain rule. Returning to the definition of acceleration:

Latex
{latex}


h5. {color:maroon} Integration with Respect to Position {color}

The definition of acceleration can also be integrated with respect to position, if we use a calculus trick that relies on the chain rule.  Returning to the definition of acceleration:

{latex}\begin{large}\[ \frac{dv}{dt} = a \] \end{large}{latex}

we

...

would

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like

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to

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find

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an

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expression

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for

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v

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as

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a

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function

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of

...

x

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instead

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of

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t

...

.

...

One

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way

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to

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achieve

...

this

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is

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to

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use

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the

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chain

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rule

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to

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write:

{
Latex
}\begin{large} \[ \frac{dv}{dx}\frac{dx}{dt} = a \] \end{large}{latex}

We

...

can

...

now

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elminate

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t

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from

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this

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expression

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by

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using

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the

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defnition

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of

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velocity

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to

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recognize

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that

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dx

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/

...

dt

...

=

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v

...

.

...

Thus:

{
Latex
}\begin{large} \[ \frac{dv}{dx}v = a \] \end{large}{latex}

which

...

is

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easily

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integrated

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for

...

the

...

case

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of

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constant

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acceleration:

{
Latex
}\begin{large} \[ \int_{v_{\rm i}}^{v} v \:dv = \int_{x_{\rm i}}^{x} a \:dx \] \end{large}{latex}

to

...

give:

{
Latex
}\begin{large}\[ v^{2} = v_{\rm i}^{2} + 2 a (x-x_{\rm i}) \] \end{large}{latex}


h5. {color:maroon} Four or Five Useful Equations {color}

The integrations performed above can be combined with the relationship between average velocity and position:
{latex}\begin{large} \[ \bar{v} = \frac{\Delta x}{\Delta t} = \frac{x - x_{\rm i}}{t- t_{\rm i}} \] \end{large}
{latex}

to give five very important equations.

{panel:title=Five (or Four) Equations for Kinematics with Constant Acceleration}
{latex}\begin{large} \[ x = x_{\rm i} + \bar{v}(t-t_{\rm i}) \] \[ \bar{v} = \frac{1}{2}(v+v_{\rm i}) \]
\[ v = v_{\rm i} + a(t-t_{\rm i}) \]\[ x = x_{\rm i} + v_{\rm i}(t-t_{\rm i}) + \frac{1}{2} a (t-t_{\rm i})^{2} \]
\[ v^{2} = v_{\rm i}^{2} + 2 a (x-x_{\rm i}) \]\end{large}{latex}
{panel}

{note}Because the first equation is not specific to the case of constant acceleration (it is simply a definition of average velocity) it is combined with the second equation in the summary on the model specification page for [one-dimensional motion with constant acceleration|1-D Motion (Constant Acceleration)]. {note}

h5. {color:maroon}The Utility of Constant Acceleration{color}

Stringing together a series of constant [velocity] segments is not usually a realistic description of motion, because real objects cannot change their velocity in a discontinuous manner. This drawback does _not_ apply to constant acceleration, however. Objects can have their acceleration changed almost instantaneously.  Because of this, it is often reasonable to approximate a complicated motion by separating it into segments of constant acceleration.



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...

The Utility of Constant Acceleration

...

Stringing together a series of constant velocity segments is not usually a realistic description of motion, because real objects cannot change their velocity in a discontinuous manner. This drawback does not apply to constant acceleration, however. Objects can have their acceleration changed almost instantaneously. Because of this, it is often reasonable to approximate a complicated motion by separating it into segments of constant acceleration.