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Excerpt
hiddentrue

Simple problem illustrating the definition of impulse and the utility of an initial-state final-state diagram.

Consider a ball of mass mb that is moving to the right at a constant speed vb when it suddenly impacts a wall and reverses direction (still moving at the same speed). What is the impulse delivered to the ball in the collision?

Solution

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System:
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The ball as a point particle.
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sys

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Interactions:
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During the impact, we assume that the collision force from the wall is vastly larger than any other external forces on the ball, so that other forces are ignored.
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Model:
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Momentum and External Force.
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Approach:

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We will solve this problem using three different approaches to illustrate alternate ways to perform vector subtraction.

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Wiki Markup
{composition-setup}{composition-setup} {table:border=1|frame=void|rules=cols|cellpadding=8|cellspacing=0} {tr:valign=top} {td:width=350px|bgcolor=#F2F2F2} {live-template:Left Column} {td} {td} {excerpt:hidden=true}Simple problem illustrating the definition of [impulse] and the utility of an [initial-state final-state diagram].{excerpt} Consider a ball of mass _m{~}b{~}{_} that is moving to the right at a constant speed _v{~}b{~}{_} when it suddenly impacts a wall and reverses direction (still moving at the same speed). What is the impulse delivered to the ball in the collision? h4. Solution {toggle-cloak:id=sys} *System:* {cloak:id=sys} The ball as a [point particle].{cloak:sys} {toggle-cloak:id=int} *Interactions:* {cloak:id=int} During the impact, we assume that the [collision force] from the wall is vastly larger than any other [external forces|external force] on the ball, so that other forces are ignored.{cloak:int} {toggle-cloak:id=mod} *Model:* {cloak:id=mod}[Momentum and External Force].{cloak:mod} {toggle-cloak:id=app} *Approach:* {cloak:id=app} We will solve this problem using three different approaches to illustrate alternate ways to perform vector subtraction. {deck:id=methoddeck} {card:label=Using Algebra} h4. Using Algebra {toggle-cloak:id=diag1} {color:red} *Diagrammatic Representation* {color} {cloak:id=diag1} {warning}The [{_}magnitude{_}|magnitude] of the [momentum|momentum] before and after the collsion is the same ({_}m{~}b{~}v{~}b{~}{_}), which can easily lead to the conclusion that there has been no change. Thinking about the situation, however, should quickly convince you that the ball has certainly been acted on by some force, which implies that a change _did_ occur. Carefully drawing the [initial-state final-state diagram] below (taking special note of the coordinate system) shows the resolution to this difficulty.{warning} |!ballreversei.png!|!ballreversef.png!| ||Initial State||Final State|| {cloak:diag1} {toggle-cloak:id=math1} {color:red} *Mathematical Representation* {color} {cloak:id=math1} The ball's initial _x_ momentum is positive in our coordinates (+{_}m{~}b{~}v{~}b{~}{_}), while its final _x_ momentum is _negative_ ( -- {_}m{~}b{~}v{~}b{~}{_}), giving a change of: {latex}
Card
labelUsing Algebra

Using Algebra

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Diagrammatic Representation

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Warning

The magnitude of the momentum before and after the collsion is the same (mbvb), which can easily lead to the conclusion that there has been no change. Thinking about the situation, however, should quickly convince you that the ball has certainly been acted on by some force, which implies that a change did occur. Carefully drawing the initial-state final-state diagram below (taking special note of the coordinate system) shows the resolution to this difficulty.

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Initial State

Final State

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Mathematical Representation

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The ball's initial x momentum is positive in our coordinates (+mbvb), while its final x momentum is negative (-- mbvb), giving a change of:

Latex
\begin{large}\[ J_{x} = -m_{b}v_{b} - m_{b}v_{b} = -2m_{b}v_{b}\]\end{large}
{latex}


where

the

negative

sign

indicates

that

the

impulse

is

applied

in

the

negative

_

x

_

direction,

and

so

the

impulse

points

leftward

in

this

case.

{cloak:math1} {card:Using Algebra} {card:label=Adding Vectors to get Final Momentum} h4. Adding to get the Final Momentum We have defined impulse as the final [momentum|momentum] minus the initial [momentum|momentum], but subtracting [vectors|vector] can be confusing. Therefore, we will first consider a rearrangement of the definition of impulse. We can write: {latex}

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Card
Using Algebra
Using Algebra

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labelAdding Vectors to get Final Momentum

Adding to get the Final Momentum

We have defined impulse as the final momentum minus the initial momentum, but subtracting vectors can be confusing. Therefore, we will first consider a rearrangement of the definition of impulse. We can write:

Latex
\begin{large}\[ \vec{p}_{f} = \vec{p}_{i} + \vec{J} \] \end{large}
{latex}


Thus,

we

can

consider

the

impulse

as

the

[vector|

vector

]

we

must

_

add

_

to

the

initial

[momentum|

momentum

]

to

yield

the

final

[

momentum

|momentum]. We can use this formulation to draw a vector diagram representing the ball-wall collision. Remembering the rules for adding [vectors|vector]

.

We can use this formulation to draw a vector diagram representing the ball-wall collision. Remembering the rules for adding vectors tail-to-tip,

we

can

draw

the

following

diagram

which

includes

the

impulse

vector:

!addimpulsevec.png! {card:Adding Vectors to get Final Momentum} {card:label=Subtracting Initial Momentum Vector from Final} h4. Subtracting Initial Momentum from Final It is also possible to draw a vector representation of the regular definition of impulse {latex}

Image Added

Card
Adding Vectors to get Final Momentum
Adding Vectors to get Final Momentum

Card
labelSubtracting Initial Momentum Vector from Final

Subtracting Initial Momentum from Final

It is also possible to draw a vector representation of the regular definition of impulse

Latex
\begin{large}\[ \vec{J} = \vec{p}_{f} - \vec{p}_{i}  \] \end{large}
{latex}


but

drawing

a

vector

equation

that

includes

subtraction

is

tricky.

We

_

must

_

think

of

this

equation

in

the

following

way:

{


Latex
}
\begin{large}\[ \vec{J} = \vec{p}_{f} + (- \vec{p}_{i})  \] \end{large}
{latex}


In

other

words,

we

must

think

of

the

right

hand

side

as

the

final

momentum

_

plus

_

the

_

negative

_

of

the

initial

momentum

vector.

Since

the

negative

of

a

vector

is

just

the

reversed

vector,

this

leads

to

the

picture:

!addneginitvec.png! which gives the same impulse vector as the diagram above. {card} {deck} {cloak:app} {td} {tr} {table} {live-template:RELATE license}


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which gives the same impulse vector as the diagram above.

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