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h4.

Using

Algebra

{

Card
labelUsing Algebra
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Diagrammatic Representation

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Warning

The magnitude of the momentum before and after the collsion is the same (mbvb), which can easily lead to the conclusion that there has been no change. Thinking about the situation, however, should quickly convince you that the ball has certainly been acted on by some force, which implies that a change did occur. Carefully drawing the initial-state final-state diagram below (taking special note of the coordinate system) shows the resolution to this difficulty.

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Initial State

Final State

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Mathematical Representation

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The ball's initial x momentum is positive in our coordinates (+mbvb), while its final x momentum is negative (-- mbvb), giving a change of:

Latex
=diag1} {color:red} *Diagrammatic Representation* {color}

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{warning}The [{_}magnitude{_}|magnitude] of the [momentum|momentum] before and after the collsion is the same ({*}{_}m{~}b{~}v{~}b{~}{_}{*}), which can easily lead to the conclusion that there has been no change.  Thinking about the situation, however, should quickly convince you that the ball has certainly been acted on by some force, which implies that a change _did_ occur.  Carefully drawing the [initial-state final-state diagram] below (taking special note of the coordinate system) shows the resolution to this difficulty.{warning}

|!ballreversei.png!|!ballreversef.png!|
||Initial State||Final State||

{cloak:diag1}

{toggle-cloak:id=math1} {color:red} *Mathematical Representation* {color}

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The ball's initial {*}_x_{*} momentum is positive in our coordinates ({*}+{_}m{~}b{~}v{~}b{~}{_}{*}), while its final {*}_x_{*} momentum is _negative_ ({*}-- {_}m{~}b{~}v{~}b{~}{_}{*}), giving a change of:
\\
{latex}\begin{large}\[ J_{x} = -m_{b}v_{b} - m_{b}v_{b} = -2m_{b}v_{b}\]\end{large}{latex}
\\
where the negative sign indicates that the impulse is applied in the negative {*}_x_{*} direction, and so the impulse points leftward in this case. 

{cloak:math1}
{card:Using Algebra}
{card:label=Adding Vectors to get Final Momentum}
h4. Adding to get the Final Momentum

We have defined impulse as the final [momentum|momentum] minus the initial [momentum|momentum], but subtracting [vectors|vector] can be confusing.  Therefore, we will first consider a rearrangement of the definition of impulse.  We can write:
\\
{latex}


where the negative sign indicates that the impulse is applied in the negative x direction, and so the impulse points leftward in this case.

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Using Algebra
Using Algebra

Card
labelAdding Vectors to get Final Momentum

Adding to get the Final Momentum

We have defined impulse as the final momentum minus the initial momentum, but subtracting vectors can be confusing. Therefore, we will first consider a rearrangement of the definition of impulse. We can write:

Latex
\begin{large}\[ \vec{p}_{f} = \vec{p}_{i} + \vec{J} \] \end{large}{latex}
\\


Thus,

we

can

consider

the

impulse

as

the

[vector|

vector

]

we

must

_

add

_

to

the

initial

[momentum|

momentum

]

to

yield

the

final

[momentum|

momentum

]

.

We

can

use

this

formulation

to

draw

a

vector

diagram

representing

the

ball-wall

collision.

Remembering

the

rules

for

adding

[

vectors

|vector]

tail-to-tip,

we

can

draw

the

following

diagram

which

includes

the

impulse

vector:

Image Added

Card
Adding Vectors to get Final Momentum
Adding Vectors to get Final Momentum

Card
labelSubtracting Initial Momentum Vector from Final

Subtracting Initial Momentum from Final

It is also possible to draw a vector representation of the regular definition of impulse

Latex


!addimpulsevec.png!
{card:Adding Vectors to get Final Momentum}
{card:label=Subtracting Initial Momentum Vector from Final}

h4. Subtracting Initial Momentum from Final

It is also possible to draw a vector representation of the regular definition of impulse
\\
{latex}\begin{large}\[ \vec{J} = \vec{p}_{f} - \vec{p}_{i}  \] \end{large}{latex}
\\
but drawing a vector equation that includes subtraction is tricky.  We _must_ think of this equation in the following 


but drawing a vector equation that includes subtraction is tricky. We must think of this equation in the following way:

Latex
way:
\\
{latex}\begin{large}\[ \vec{J} = \vec{p}_{f} + (- \vec{p}_{i})  \] \end{large}{latex}
\\
In other 


In other words,

we

must

think

of

the

right

hand

side

as

the

final

momentum

_

plus

_

the

_

negative

_

of

the

initial

momentum

vector.

Since

the

negative

of

a

vector

is

just

the

reversed

vector,

this

leads

to

the

picture:

\\ !addneginitvec.png! \\ which gives the same impulse vector as the diagram above.


Image Added
which gives the same impulse vector as the diagram above.

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