Part A

    A person pushes a box of mass 15 kg along a floor by applying a perfectly horizontal force F. The box accelerates horizontally at a rate of 2.0 m/s2. Assuming the coefficient of kinetic friction between the box and the ground is 0.45, what is the magnitude of F?

    Solution

    System:

    Box as point particle.

    Interactions:

    External influences from the person (applied force) the earth (gravity) and the floor (normal force and friction).

    Model:

    Point Particle Dynamics.

    Approach:

    Diagrammatic Representation

    The free body diagram for this situation is:

    Mathematical Representation

    With this free body diagram, Newton's 2nd Law can be written:

    where we have assumed that the y acceleration is zero because the box is sliding along a horizontal floor, not moving upward or downward. This realization is important, because we know Ff = μN. Thus, because the y acceleration is zero, we can solve Newton's 2nd Law in the y direction to yield:

    so that:

    Part B

    A person pushes a box of mass 15 kg along a floor by applying a perfectly horizontal force F. The box moves horizontally at a constant speed of 2.0 m/s in the direction of the person's applied force. Assuming the coefficient of kinetic friction between the box and the ground is 0.45, what is the magnitude of F?

    System, Interactions and Model:

    As in Part A.

    Approach: