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M_{2}a_{net}=D_{2}+M_{2}g-N\\ N=D_{2}+M_{2}g-M_{2}a_{net}\\ N=\frac{M_{1}D_{2}-M_{2}D_{1}}{M_{1}+M_{2}} |
It is reassuring to see that the results for N are the same when solving via System 1 as when solving by means of System 2. This gives us confidence in our answer.
These results tell us that drag separation will occur (N<0) if M2 is sufficiently large and/or D1 is sufficiently large.