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Mathinline
body\sigma_{burst} = \sigma_{tensile \ yield} = 276*10^6 Pa \approx 40030 psi

Applying P = F*/A where F is 720 lbs at burst and A is the area of bore, we find:

Mathinline
body\frac{\sigma_{burst}*t*A}{FAF} = r

Then, assuming a circular bore, area takes the form A = πr2

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