...
Using the equation from earlier, we can calculate what the shear stress due to the bolts will be. However since there are two distances from the holes to the edge of the case and we have an equal number of bolts on each row, we will average them to use in the equation.
Size Thickness of hole Wall = 0.25 in
A = 0.25*(1.63 + 0.63)/2 = 0.28 in^2
Now we can calculate the shear stress:
P = 826 PSI
d = 4 in
Num Bolts = 24
T_shear = (826*(4/2)^2*pi)/(24*2*0.28) = 772 PSI
This amount of shear is significantly lower than the shear modulus of aluminum, so this should not be a concern.