Versions Compared

Key

  • This line was added.
  • This line was removed.
  • Formatting was changed.

For the injector faceplate to stay fastened to the manifold, the bolts must satisfy a factor of safety for both tensile and shear stress. A net upward pressure acting on the faceplate applied to the area of the injector requires all bolts on the injector manifold -both axial and radial- to withstand this force to maintain structural integrity.


Desmos: https://www.desmos.com/calculator/erjdwzmlve

The area of the bolt can be determined by using its pitch diameter, which is calculated using its major diameter and the spacing between each thread:

Mathdisplay
\begin{align*}
& D_{pitch} = D_{major} - (0.6495*t_s) \\
& A_{bolt} = πr^2 = π(\frac{d_{pitch}}{2})^2 = \frac{1}{4}πd_{pitch}^2
\end{align*}


Tensile Stress on Each Axial Bolt During Hot Fire:


Mathdisplay
\begin{align*}
& F_{up} = P_{injector}*A_{injector} \\
& F_{up} + (N*F_{bolt})=0 \\
& \\
&|F_{bolt}| = \frac{P_{injector}*A_{injector}}{N} \\
& \\
& Stress_{Tensile}: σ_{hot} = \frac{|F_{bolt}|}{A_{bolt}} = \frac{P_{injector}*A_{injector}}{N*A_{boltaxial}} \\
& \\
& σ_{steel} = σ_{steel} \\
\end{align*}


Shear Stress on Each Radial Bolt During Hot Fire and Approximation of Shear Strength:

Mathdisplay
\begin{align*}
& F_{up} = P_{injector}*A_{injector} \\
& F_{up} + (N*F_{bolt})=0 \\
& \\
&|F_{bolt}| = \frac{P_{injector}*A_{injector}}{N} \\
& \\
& Stress_{Shear}: τ_{hot} = \frac{|F_{bolt}|}{A_{bolt}} = \frac{P_{injector}*A_{injector}}{N*A_{boltradial}} \\
& \\
& τ_{steel} ≈ \frac{σ_{steel}}{\sqrt{3}} \\
\end{align*}


Factor of Safety for Tensile Stress and Shear Stress During Hot Fire:

Mathdisplay
\begin{align*}


&
F
 FOS_{
up
tensile} =
P
 \frac{σ_{
injector
steel}
*A_{injector
}
\\
& F_{up} + (N*F
_{
bolt})=0 \\
& \\
&|F_{bolt}| =
hot}} = \frac{
P
σ_{
injector
steel}}
*A
N_{
injector}}{N}
axial} \\

& \\
& Stress

& FOS_{
Shear
shear}
: τ
 = \frac{
|F
τ_{
bolt
steel}
|}
{
A
τ_
{bolt
hot}
}
 = \frac{
P_{injector}*A_{injector}}{N*A_{bolt}} \\ & \\ & τ_{steel} ≈ \frac{
σ_{steel
}
}{\sqrt{3}τ_hot}\\
\end{align*}