Spinning Top |
The rapidly spinning Symmetric Top exhibiting Precession under the force of [Gravity] is a classic Physics problem.
We assume that we have a symmetric top that can easily rotate about an axis containing its center of mass at a high angular velocity ω . If the top tilts at all from the vertical, so that its center of mass does not lie directly above the top's point of contact with the surface it's resting on, there will be a [torque (one-dimensional)] exerted on the top, which will act to change its [angular momentum (one-dimensional)]. What will happen?
Solution
System:
Interactions:
[torque
due to [gravity] and normal force from the surface the top is spinning on.
Model:
Approach:
Diagrammatic Representation
First, consider the Y support for the pendulum:
Unable to render embedded object: File (Lissajous Figure 1.PNG) not found.
The pendulum effectively has length L2 when swinging in the horizontal plane in and out of the page, but length L1 along the horizontal direction in the plane of the page.
Unable to render embedded object: File (Lissajous Pendulum 2.PNG) not found.
Mathematical Representation
We ignore the distribution of tensions in the upper cables, and simply view the pendulum as a simple pendulum along either the plane of the drawing or perpendicular to it. In the plane perpendicular to the drawing (where the mass oscillates toward and away from the reader) the pendulum length is L2 and the angular frequency of oscillation is given by the formula for the Simple Pendulum (see Simple Harmonic Motion.
\begin
[ \omega_
= \sqrt{\frac
{L_
}} ]\end
Along the plane lying in the page, where the mass moves left and right, the pendulum length is the shorter L1 and the angular frequency is
\begin
[ \omega_
= \sqrt{\frac
{L_
}} ]\end
the ratio of frequencies is thus:
\begin
[ \frac{\omega_{2}}{\omega_{1}}= \frac{\sqrt{\frac
{L_{2}}}}{\sqrt{\frac
{L_{1}}}} = \sqrt{\frac{L_{1}}{L_
}} ]\end
in order to have a ratio of 1:2, one thus needs pendulum lengths of ratio 1:4. In order to get a ratio of 3:4 (as in the figure at the top of the page), the lengths must be in the ration 9:16.